Quick question. Point-Slope. Thanks

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The discussion centers on converting a point-slope equation into standard form. The user starts with the point (4, -3) and a slope of -2, correctly deriving the slope-intercept form as y = -2x + 5. Confusion arises when transitioning to standard form, 2x + y = 5, which requires rearranging the equation by adding 2x to both sides. The importance of adhering to the required form for the answer is emphasized, as failing to do so may result in partial credit. Understanding the distinction between slope-intercept and standard forms is crucial for correctly completing the problem.
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**Quick question. Point-Slope. Thanks!

Homework Statement



Ok i get all of it, except that last part. Here ill show you. Point-Slope question.

(4, -3), m = -2

so...

y + 3 = -2(x - 4) which then becomes y+3 = -2x + 8)

Then...

subtract 3 from y + 3, and then do it on other side

which then gives you:

y = -2x + 5

Now, I don't get this final part. It says that you go y + 2x, and then -2x + 2x

which gives you: 2x + y = 5

I don't get why and how you do that last part? Can anyone please explain?


Homework Equations





The Attempt at a Solution

 
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Take a look at what eumyang wrote about the properties of equations in post 6 of this thread.

Rather than repeat what he wrote, it would be better if you took a closer look at that.
 


Also, you have to be mindful of which form the answer needs to be in. You didn't specify this in your problem, but I'm guessing that it was supposed to be in standard form, because you say at the end
2x + y = 5
which is the standard form of the equation of a line (Ax + By = C). That would be the reason why one would add 2x to both sides in the last step.

If instead you stopped at
y = -2x + 5,
then you would have the answer in the wrong form (the above is slope-intercept form). If I were grading this I would have given partial credit because you didn't follow directions.


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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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