Radial component of del^2 in spherical coordinates? (again)

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Homework Help Overview

The discussion revolves around the radial component of the Laplacian operator (del^2) in spherical coordinates, specifically in the context of a 3D isotropic harmonic oscillator. Participants are examining the mathematical representation and implications of the radial component as presented by a lecturer.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to clarify the expression for the radial component of del^2 and questions the relationship between dr and del^2. Other participants discuss the derivation of the terms involved, referencing the product rule and specific mathematical forms.

Discussion Status

Participants are actively engaging with the mathematical expressions and exploring the implications of the terms involved. Some guidance has been offered regarding the use of the product rule, but there is no explicit consensus on the interpretations or final forms of the equations being discussed.

Contextual Notes

There are references to external resources that may not have provided sufficient clarity, and some participants express confusion regarding specific transformations and terms in the equations. The discussion reflects a mix of attempts to understand the mathematical framework without resolving all uncertainties.

philip041
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I'm doing a question on a 3D isotropic harmonic oscillator. At one point I need to find write the radial component of del^2.

Lecturer has written

[tex] <br /> \frac{1}{r^{2}} \frac{d}{dr} \left( r^{2} \frac{d}{dr} \right)<br /> [/tex]

where the del^2 used to be in the set of equations.

Am I correct in saying the radial part of in spherical polar coordinates is just dr. Then del^2 would be dr^2? Well I'm not?

I had a look at http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html but it didn't explain anything more for me.

PS. I asked this question earlier but internet broke, (thanks virgin media), and I don't understand the answer given... https://www.physicsforums.com/showthread.php?p=2006618#post2006618
 
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philip041 said:
I'm doing a question on a 3D isotropic harmonic oscillator. At one point I need to find write the radial component of del^2.

Lecturer has written

[tex] <br /> \frac{1}{r^{2}} \frac{d}{dr} \left( r^{2} \frac{d}{dr} \right)<br /> [/tex]

where the del^2 used to be in the set of equations.

Am I correct in saying the radial part of in spherical polar coordinates is just dr. Then del^2 would be dr^2? Well I'm not?

I had a look at http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html but it didn't explain anything more for me.

Hi philip041! :smile:

(have a theta: θ and a phi: φ and a curly d: ∂ :wink:)

isotropic means dθ = dφ = 0

so in http://hyperphysics.phy-astr.gsu.edu/hbase/sphc.html at http://hyperphysics.phy-astr.gsu.edu/hbase/lapl.html#c2, the only non-zero terms in the last line are ∂2f/∂r2 + 2/r ∂f/∂r,

which is the same as 1/r2 d/dr(r2d/dr) :smile:
 
Last edited by a moderator:
Thanks,

With ∂^2f/∂r^2 + 2/r ∂f/∂r how come it doesn't go to ∂^2/∂r^2 -1/r^2?

Sorry I don't understand how you get to that final line you wrote.
 
product rule

philip041 said:
With ∂^2f/∂r^2 + 2/r ∂f/∂r how come it doesn't go to ∂^2/∂r^2 -1/r^2?

uhhh? how did you get -1/r^2? :confused:

Hint: use the product rule to find d/dr(r2df/dr) :smile:
 
sweet. i also found an explanation of this in zetilli appendix b of quantum mechanics if anyone should ever search for this thread...
 

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