Radicals-> Exponential equations

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To express the cube root of the square root of 2 as an exponential equation, start with the square root of 2, which is 2^(1/2). The cube root can be represented as raising to the power of 1/3, resulting in the expression (2^(1/2))^(1/3). This simplifies to 2^(1/2 * 1/3), which equals 2^(1/6). The final step is to convert this back into radical form, yielding the sixth root of 2. The discussion highlights the process of simplification and conversion between exponential and radical forms.
rock4christ
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how would I take the cube root of the square root of 2 as an exponential equation? the square root of 2 is 21/2 but I don't know what to do with the cube root.
 
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The cubed root of x is x1/3. So, your expression for the cubed root of the square root of 2 is (2^{\frac{1}{2}})^{\frac{1}{3}}. Can you simplify this?
 
well Id have to simplify it, because I am supposed to turn the new simplified exponent to a radical
 
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Was that an answer to Cristo's question?? He asked do you know HOW to simplify it.
 
oh, no i don't know how
 
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