- #1
jess1
- 4
- 0
hello, i made this account just so i could figure this out--i realize people often do that (to make an account without an initial intention of becoming a regular), so i apologize for that; if you feel i am taking advantage of your time and expertise, then i understand. but i am not trying to figure this out for homework or for an upcoming test or anything like that. i just am really interested and don't have the knowledge to figure it out myself and i can't find a good explanation online.
so, of course i have heard that the best way to get the highest score (via guessing) is to just guess the same answer every time, as opposed to guessing randomly on every question, and that makes sense, but what i could not figure out was how to just prove it mathematically. i haven't taken stats :(
i figured the best way to look at it is to take 5 problems with 5 choices each and assume that each letter will be the correct answer 1 time. makes sense right? small sample size that is representative of an infinitely large one?
1) A B C D E
2) A B C D E
3) A B C D E
4) A B C D E
5) A B C D E
so to answer E every time you would be guaranteed one correct answer in the average 5-question set. but then if you answer E 4 times and leave the 5th problem blank. that gives you an 80% chance of getting one answer correct? or does it just give you an 80% chance of getting E correct and not any answer overall?
so let's say i answer A for number 5. clearly the probability of getting one right in an average 5-question set goes down?
so i have a 20% chance of getting #5 right and an 80% chance of getting 1, 2, 3, or 4 right.
i'm just going to stop though because i do not think i am on the right track if i am even right in the first place. this is frustrating. surely there is a simple permutation or something that will solve this easily?
so, of course i have heard that the best way to get the highest score (via guessing) is to just guess the same answer every time, as opposed to guessing randomly on every question, and that makes sense, but what i could not figure out was how to just prove it mathematically. i haven't taken stats :(
i figured the best way to look at it is to take 5 problems with 5 choices each and assume that each letter will be the correct answer 1 time. makes sense right? small sample size that is representative of an infinitely large one?
1) A B C D E
2) A B C D E
3) A B C D E
4) A B C D E
5) A B C D E
so to answer E every time you would be guaranteed one correct answer in the average 5-question set. but then if you answer E 4 times and leave the 5th problem blank. that gives you an 80% chance of getting one answer correct? or does it just give you an 80% chance of getting E correct and not any answer overall?
so let's say i answer A for number 5. clearly the probability of getting one right in an average 5-question set goes down?
so i have a 20% chance of getting #5 right and an 80% chance of getting 1, 2, 3, or 4 right.
i'm just going to stop though because i do not think i am on the right track if i am even right in the first place. this is frustrating. surely there is a simple permutation or something that will solve this easily?