Random Translational Kinetic Energy

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SUMMARY

The total random translational kinetic energy of 5.10 L of hydrogen gas, with a molar mass of 2.016 g/mol, at a pressure of 1.04×105 Pa and a temperature of 301 K, is calculated using the formula K = 3/2 nRT. The calculations confirm that K = 772.62 J, derived from the ideal gas law PV = nRT. This result is validated by multiple contributors in the discussion, affirming the accuracy of the approach and the simplicity of the calculation.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Familiarity with kinetic energy equations in thermodynamics
  • Basic knowledge of gas properties and molar mass calculations
  • Proficiency in unit conversions (liters to cubic meters)
NEXT STEPS
  • Study the derivation of the Ideal Gas Law and its applications
  • Learn about the relationship between temperature and kinetic energy in gases
  • Explore advanced thermodynamic concepts such as heat capacity
  • Investigate the behavior of real gases versus ideal gases
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Students in physics or chemistry, educators teaching thermodynamics, and professionals in fields requiring gas behavior analysis will benefit from this discussion.

Punkyc7
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What is the total random translational kinetic energy of 5.10 L of hydrogen gas (molar mass 2.016g/mo with pressure 1.04×10^5 Pa and temperature 301 K?

K=3/2nRT
Pv=nRT

P=1.01*10^5
V=5.1*10^-3

Is it just

PV/RT=n
K=3/2(PV/RT)(RT)

K=3/2 PV

K=772.62 J

Is that right because that seems too easy
 
Last edited:
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It is right.

ehild
 

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