- #1
Punkyc7
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What is the total random translational kinetic energy of 5.10 L of hydrogen gas (molar mass 2.016g/mo with pressure 1.04×10^5 Pa and temperature 301 K?
K=3/2nRT
Pv=nRT
P=1.01*10^5
V=5.1*10^-3
Is it just
PV/RT=n
K=3/2(PV/RT)(RT)
K=3/2 PV
K=772.62 J
Is that right because that seems too easy
K=3/2nRT
Pv=nRT
P=1.01*10^5
V=5.1*10^-3
Is it just
PV/RT=n
K=3/2(PV/RT)(RT)
K=3/2 PV
K=772.62 J
Is that right because that seems too easy
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