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Random Translational Kinetic Energy

  1. Aug 8, 2011 #1
    What is the total random translational kinetic energy of 5.10 L of hydrogen gas (molar mass 2.016g/mo with pressure 1.04×10^5 Pa and temperature 301 K?

    K=3/2nRT
    Pv=nRT

    P=1.01*10^5
    V=5.1*10^-3

    Is it just

    PV/RT=n
    K=3/2(PV/RT)(RT)

    K=3/2 PV

    K=772.62 J

    Is that right because that seems too easy
     
    Last edited: Aug 8, 2011
  2. jcsd
  3. Aug 8, 2011 #2

    ehild

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    It is right.

    ehild
     
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