Rate Law for A+B Reaction: k[A][B]^2

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The rate law for the reaction 2A + 3B → products is determined to be rate = k[A][B]^2, indicating it is first order in A and second order in B. The confusion arises from misinterpreting the orders; first order means the rate is proportional to the concentration of A, while second order means it is proportional to the square of the concentration of B. Therefore, the correct formulation combines these orders appropriately. Understanding these definitions clarifies the correct rate law expression. This highlights the importance of accurately interpreting reaction orders in rate laws.
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) If the rate law for the reaction
2A + 3B → products
is first order in A and second order in B, then the rate law is rate

I initially thought the answer would be k[A]^2 but it's wrong, the correct answer is
k[A]^2
Could anyone explain?? Please, thank you!
 
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"first order in A" means "Proportional to [A]"

"Second order in B" means "Proportional to 2."

Put those together and what do you get?
 
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