Rate of Change - Just checking

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SUMMARY

The discussion focuses on calculating the rate of change of height in a conical pile of sand, where the height equals the diameter. The volume of the cone is given by the formula \(v = \frac{1}{3}\pi r^2 h\), and the sand is poured at a constant rate of 5 m³/s. The solution involves differentiating the volume with respect to time and using the relationship \(r' = \frac{h'}{2}\) to find that the height \(h'\) is increasing at a rate of \(\frac{5}{\pi}\) m/s when the height is 2 meters. The final answer is confirmed as correct by other participants in the discussion.

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[SOLVED] Rate of Change - Just checking

Homework Statement



Sand is poured into a conical pile with the height of the pile equaling the diameter of the pile. If the sand is poured at a constant rate of 5m^3/s at what rate is the height of the pile increasing when height is 2 meters.

Homework Equations



v = [tex](1/3)\pi r^2[/tex]
r' = h' / 2 (i think this is right - not sure)

The Attempt at a Solution



So i got
v' = [tex](1/3)\pi (2rr'h + r^2h')[/tex]

So i have 2 unknowns r' and h'. Since we can make the connection that r' = h'/2 i replace that in the equation and get:

v' = [tex](1/3)\pi (2r(h'/2)h + r^2h')[/tex] ->

r = 1
h = 2

SO:

v' = [tex](1/3)\pi (2h' + h')[/tex] ->
h' = [tex]5/\pi[/tex]

Im not sure if this answer is right but if you can please check over my work, i would appreciate it.

Thanks!
 
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It would have been better to have clearly stated somewhere that v'= 5, but it's obvious that you did use that. Yes, that is the correct answer.
 
Sorry i thought it was in the problem question i posted.

Well thanks!
 

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