Rate of Production with Given Information

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The discussion focuses on calculating the rate of oxygen (O2) release from the decomposition of potassium chlorate (KClO3). Given that 0.20 g of KClO3 decomposes in 2.8 seconds, the rate of decomposition is calculated to be 0.000583 mol/s. Participants mention the need to apply the ideal gas law (n = PV/RT) to determine the rate of O2 produced at standard ambient temperature and pressure (SATP). The conversation highlights the conversion of KClO3 to moles and the subsequent calculations leading to the rate of decomposition. Further assistance is sought to complete the calculation for the rate of O2 release.
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Homework Statement



2 KClO3 (s) + heat --> 2 KCl (s) + 3 O2 (g)

If 0.20 g of KClO3 (s) decomposes in 2.8 s, at what rate is oxygen O2 (g) released over this time at SATP?

Homework Equations



n = PV/RT

The Attempt at a Solution



Converted KClO3 to mol.

.20 x 1 / 122.5495g = 0.001632 mol KCl

Find rate of decomposition :

.001632 mol in 2.8 sec --> 2 mol in 3431.37 sec

2/3431.37 = .000583 mol/s

The rate of decomposition of KClO3 is .000583 mol/s

I'm stuck at this part. I know I need to use some sort of n = PV/RT since it tells me that it is at SATP. Can I have some hints or help?
 
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Complex_ said:
0.001632 mol KCl
Check.
Complex_ said:
.000583 mol/s
Check.
Complex_ said:
at what rate is oxygen O2 (g)
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