Rather easy problem involving set multiplication

U.Renko
Messages
56
Reaction score
1

Homework Statement


A = { 1, 1, 2, 5}
B = [1, 2]

find A x B

Homework Equations


not much

The Attempt at a Solution



well, the problem itself seems easy enough
The thing is, I'm not very sure what it means to multiply a set by an interval...

just need a little help with this detail
 
Physics news on Phys.org
But what's confusing is that the set {1,1,2,5} is the same as {1,2,5}, by basic set properties.

One way of understanding the product of a set by an interval is by considering a subset
of the product of 2 intervals, say , the interval [1,5], and [1,2] , then {1,2,5}x [1,2] will
just give you three discrete copies of the interval [1,2]. Or look at the square [0,1]x[0,1] , then {0,1}x[0,1] are just the bottom and the top of the square, respectively.
 
You could express the result using set builder notation.

For example:

{1,3}×[0,1] = {(1,y)|0≤y≤1} ∪ {(3,y)|0≤y≤1}

= {(x,y)|x∊{1,3}, 0≤y≤1}
 
SammyS said:
You could express the result using set builder notation.

For example:

{1,3}×[0,1] = {(1,y)|0≤y≤1} ∪ {(3,y)|0≤y≤1}

= {(x,y)|x∊{1,3}, 0≤y≤1}


The thing is, in the book I'm using, up to this exercise, Unions and the such were not defined yet.

also I'm not 100% sure that {1,1,2,5} = {1,2,5}
shouldn't one have cardinality 4 and the other cardinality 3 ?

might make some difference.
 
List the elements in each set. {1,1,2,5} ; {1,2,5} .
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top