Rating speeds from least to greatest from a position time graph

  • Thread starter Thread starter Ineedhelpwithphysics
  • Start date Start date
  • Tags Tags
    Physics 1 Speed
AI Thread Summary
The ranking of speeds from least to greatest based on the position-time graph is R > P > Q = S. R has a steeper slope than P, indicating a greater speed. P has a positive slope, confirming it has a non-zero speed. Both Q and S have horizontal slopes, indicating no movement and therefore zero speed. The explanations provided for the rankings are accurate.
Ineedhelpwithphysics
Messages
43
Reaction score
7
Homework Statement
(E) Rank the values of the particles speed at points P, Q, R, S from fastest to slowest
Relevant Equations
Speed = distance/time
My answer is R > P > Q = S

Since R is more steeper than P the speed is greater, speed is a non-negative unit so i assume that speed of R will be greater than P
Speed of P has a positive slope, also the magnitude is positive.
Q and S are the same due to the fast that they both horizontal slopes which means the object is not moving which means no speed.

This is my work , correct me if i'm wrong, thanks ^^^
1706021404345.png
 
Reply
  • Like
Likes PhDeezNutz and Delta2
Physics news on Phys.org
Ranking and explanations look good.
 
Reply
  • Like
Likes PhDeezNutz, erobz, Delta2 and 1 other person
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »
Thread 'Minimum mass of a block'

Thread 'Minimum mass of a block'

Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
View full post »

Similar threads

Velocity required to escape the solar system
Replies
15
Views
1K
Where Did I Go Wrong in My Refraction Problem Solution?
Replies
11
Views
2K
Finding change in speed from x vs t graph
Replies
29
Views
5K
MIT OCW, 8.02 Electromagnetism: Potential for an Electric Dipole
Replies
1
Views
2K
A child rolls a marble....Plot graphs etc.
Replies
4
Views
5K
Traveling Car Physics Question - Comparing Speed & acceleration
Replies
5
Views
7K
Elliptical orbit/ determine speed & potential energy
Replies
1
Views
1K
Flux and Induced EMF vs displacement graphs
Replies
7
Views
5K
Net force acting on positive charge
Replies
1
Views
2K
Solving Orbital Speed with Energy & Angular Momentum Conservation
Replies
7
Views
2K

Hot Threads

Recent Insights

Back
Top