Ratio of Resultant Wave to Common Amplitude: Pi/2 Rad Out of Phase

AI Thread Summary
Two identical traveling waves that are out of phase by Pi/2 radians result in a specific amplitude ratio that is not simply additive. The confusion arises from the assumption that amplitudes can be directly summed, which is only true for in-phase waves. For waves that are 90 degrees out of phase, the resultant amplitude can be calculated using the Pythagorean theorem, leading to a maximum amplitude that is less than the sum of the individual amplitudes. The resultant amplitude is determined by the equation A_r = √(A^2 + A^2), where A is the common amplitude of the waves. Understanding this concept is crucial for accurately determining the ratio of the resultant wave's amplitude to the common amplitude.
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Two identical traveling waves, moving in the same direction, are out of phase by Pi/2 rad.
(a) What is the ratio of the amplitude of the resultant wave to that of the common amplitude of the waves

I'm having trouble with this problem because I feel like I'm not given enough information, although I know that's not really the case. Does anyone have any recommendations as to where I can look up some information that can help me with this problem?
 
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Can you write the equation for each of the traveling waves? Or even just add two sine waves that are out of phase by pi/2 -- what is the max amplitude?
 
I thought I was suppose to add the two amplitudes to get the resultant amplitude but I wasn't sure if that was if they were right on top of each other. Doing this would make the ration 2:1 but I don't think that's right.
 
It's only 2:1 if they are in phase. If they are 180 degrees out of phase, you get zero when you add them, right? And if they are 90 degrees off, you get some value in between 2:1 and 0. How can you figure out the peak amplitude of the addition?
 
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