Rationale for 6n+2 rule for the number of pi bonds in a non-cyclic molecule

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Discussion Overview

The discussion revolves around the "6n+2 rule" for determining the number of pi bonds in non-cyclic molecules, exploring its origins, applications, and underlying rationale. Participants examine the relationship between the rule and molecular structure, particularly in organic chemistry.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant describes the "6n+2 rule" and its formula, noting its introduction in a specific article and expressing curiosity about its underlying rationale.
  • Another participant relates the rule to a formula for saturated alkanes, suggesting equivalence and providing an alternative perspective on calculating unsaturation in molecules.
  • A third participant expresses appreciation for the rule and proposes an additional formula for hydrocarbon chains, indicating a potential connection to the original rule.
  • A later reply acknowledges a mentor's assistance in refining a previous post, indicating collaborative engagement in the discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the rationale behind the "6n+2 rule," with some proposing alternative formulations and interpretations. The discussion remains exploratory, with multiple viewpoints presented.

Contextual Notes

Some participants express uncertainty about the applicability of the rule to various types of molecules, particularly regarding the necessity of focusing on organic compounds. There is also a mention of the complexity of valence electron calculations and how different atoms may affect the formulas used.

nomadreid
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In several websites there is a rule of thumb to determine the number of pi bonds in a non-cyclic molecule called the "6n+2 rule", in which n = the number of non-hydrogen atoms in the molecules, and V = total number of valence electrons, so that the number of electrons involved in pi bonds is 6n+2-V (i.e., the number of pi bonds is (6n+2-V)/2. This rule was introduced in the article "Lewis Structures and the octet rule. An automatic procedure for writing canonical forms." by Lever, A.B.P. in the J.Chem Educ. 1972. 49(12), pages 819-821. Unfortunately, there is a paywall to this article, and none of the websites which are freely available explain why the rule (generally) works. I considered that the number 6 might have something to do with a maximum of three sigma bonds around an atom and the 2 to do with a hydrogen bond, but that didn't pan out. (Also, the examples tend to be organic molecules, but is this necessary?) In short, why does the rule work (when it works)? Thanks very much for any pointers.
 
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I hadn't heard of this rule, but it is equivalent to the one I learnt back in the day. A saturated alkane has the formula CnH2n+2, and the number of units of unsaturation (which can include pi bonds and rings) is half the deficiency of H atoms, i.e. for a molecule CnHm it is equal to (2n+2-m)/2.

If we consider each C atom to have 4 valence electrons and each H atom 1, V = 4n+m and your formula becomes the same as mine. (I think mine is easier because you don't have to work out the number of valence electrons.)

Note that -O- or -NH- is isoelectronic with -CH2-, with 6 valence electrons, so you can use the same formula in your formulation, with n the number of non-H atoms. (In mine, you ignore O's and subtract 1H for every N; n remains the number of C atoms.)
 
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Thanks very much, mjc123. This is a very good new rule for me! (Well, all of them are new to me, as Chemistry is not my field). I will add it to the list that I am making of such rules. (I think I have figured out why the 6n+2 rule (usually) works, and the next one -- that appears the easiest to show -- is for hydrocarbon chains, that if X= number of carbon atoms, Y= number of hydrogen atoms, then the number of pi bonds is (2X-Y)/2 +1. )
 
Thanks to the mentor Berkeman who cleaned up my post a bit.
 

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