Prove that f(x) = 3*x + 11 is uniformly continuous

In summary, we can prove that f(x) = 3*x + 11 is uniformly continuous by showing that for any given e>0, we can find a corresponding d>0 such that |f(x)-f(y)| < e for all x,y in S where |x-y| < d. This is achieved by setting d = e/3 and showing that |3(x-y)| < e.
  • #1
squaremeplz
124
0

Homework Statement



Prove that f(x) = 3*x + 11 is uniformly continuous.

Homework Equations



x,y in S and |x-y| < a imply |f(x)-f(y)| < e


The Attempt at a Solution



following the book I get to

f(x) - f(y) = 3(x-y)

i just don't know how to chose e in this case..

would it be |f(x) - f(y)| < e/3

any pointers are greatly appreciated
 
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  • #2
The idea is that you can make f(a) arbitrarily close to f(b) by specifying how close a must be to b, regardless of where a and b are.

So if you wanted f(a) to be within 0.03 of f(b), how close must a be to b?
 
  • #3
squaremeplease said:

Homework Statement



i just don't know how to chose e in this case..

would it be |f(x) - f(y)| < e/3

any pointers are greatly appreciated

You already did, you just forgot to say that the proof was done. By the time you get to | f(x) - f(y) | = | 3(x-y) | then look, you know you can make (x-y) smaller than some d, how small? Smaller than e/3. Then it follows that for e>0
if |(x-y)| < d = (e/3) then |3(x-y)| < 3*(e/3) = e
 

1. What is continuity in real analysis?

Continuity is a fundamental concept in real analysis that describes the smoothness or connectedness of a function. It means that the function has no abrupt changes or breaks in its graph and can be drawn without lifting the pencil from the paper.

2. How is continuity defined mathematically?

In real analysis, a function f is continuous at a point a if the limit of f(x) as x approaches a exists and is equal to f(a). This can also be expressed using the delta-epsilon definition, which states that for any given epsilon, there exists a delta such that if the distance between x and a is less than delta, the distance between f(x) and f(a) will be less than epsilon.

3. What is the difference between pointwise and uniform continuity?

Pointwise continuity means that a function is continuous at each individual point in its domain, while uniform continuity requires that the function remains continuous over the entire domain. In other words, for uniform continuity, the value of delta can be chosen independently of the point a, whereas for pointwise continuity it may depend on the specific point.

4. Can a function be continuous but not differentiable?

Yes, a function can be continuous without being differentiable. For example, the absolute value function is continuous at all points, but it is not differentiable at x = 0. This is because the derivative of the absolute value function is undefined at that point.

5. How is continuity related to the intermediate value theorem?

The intermediate value theorem states that if a continuous function takes on two different values at two points in its domain, then it must also take on all values in between those two points. In other words, a continuous function cannot "jump over" a value. This theorem is often used to prove the existence of solutions to equations that cannot be solved algebraically.

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