Real Analysis Continuity problem.

quantchem
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Homework Statement



Show that |f(x) - f(y) | < |x - y| if f(x) = sqrt(4+x^2) if x is not equal to xo. What does this prove about f?


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The Attempt at a Solution



Already proved the first part. I am guessing that for the second part the answer is that f is continuous but I am not really sure how to show it. Please help.
 
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Well, sure. It's continuous. What's the definition of continuity?
 
I did this :

let
|f(x) - f(y) | < epsilon and |x - y| < delta. then epsilon < delta and therefore for each epsilon > 0, there is some delta > 0 such that |f(x) - f(y) | < epsilon when |x - y| < delta. so f is continuous at y when x is in an interval where f is defined.

Is this sufficient explanation?
 
quantchem said:
I did this :

let
|f(x) - f(y) | < epsilon and |x - y| < delta. then epsilon < delta and therefore for each epsilon > 0, there is some delta > 0 such that |f(x) - f(y) | < epsilon when |x - y| < delta. so f is continuous at y when x is in an interval where f is defined.

Is this sufficient explanation?

Sure. So given any epsilon, you can pick delta=epsilon and satisfy the requirements of continuity, right?
 
yup. thanks.
 
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