Real Analysis Continuity problem.

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Homework Help Overview

The problem involves demonstrating the continuity of the function f(x) = sqrt(4+x^2) under certain conditions, specifically when x is not equal to a particular value xo. The inquiry centers around the implications of the inequality |f(x) - f(y)| < |x - y|.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of continuity and its application to the function in question. Some explore the relationship between epsilon and delta in the context of continuity, while others express uncertainty about the sufficiency of their explanations.

Discussion Status

The discussion includes various interpretations of continuity and the conditions under which the function is continuous. Some participants offer guidance on the definition of continuity and its implications, while others seek confirmation of their reasoning without reaching a definitive consensus.

Contextual Notes

There is a mention of specific conditions regarding the function's definition and the variable x, which may affect the continuity discussion. Participants also reflect on the adequacy of their explanations in relation to the formal definition of continuity.

quantchem
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Homework Statement



Show that |f(x) - f(y) | < |x - y| if f(x) = sqrt(4+x^2) if x is not equal to xo. What does this prove about f?


Homework Equations





The Attempt at a Solution



Already proved the first part. I am guessing that for the second part the answer is that f is continuous but I am not really sure how to show it. Please help.
 
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Well, sure. It's continuous. What's the definition of continuity?
 
I did this :

let
|f(x) - f(y) | < epsilon and |x - y| < delta. then epsilon < delta and therefore for each epsilon > 0, there is some delta > 0 such that |f(x) - f(y) | < epsilon when |x - y| < delta. so f is continuous at y when x is in an interval where f is defined.

Is this sufficient explanation?
 
quantchem said:
I did this :

let
|f(x) - f(y) | < epsilon and |x - y| < delta. then epsilon < delta and therefore for each epsilon > 0, there is some delta > 0 such that |f(x) - f(y) | < epsilon when |x - y| < delta. so f is continuous at y when x is in an interval where f is defined.

Is this sufficient explanation?

Sure. So given any epsilon, you can pick delta=epsilon and satisfy the requirements of continuity, right?
 
yup. thanks.
 

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