Real analysis: Integrable function

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Homework Help Overview

The discussion revolves around the conditions for a function to be integrable in the context of Fourier transforms, specifically examining the implications of a function approaching zero at infinity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore whether the condition of a function being integrable implies that it approaches zero at infinity. Questions arise about the sufficiency of this condition and the existence of counterexamples.

Discussion Status

The discussion includes attempts to clarify the relationship between a function's behavior at infinity and its integrability. Some participants provide counterexamples to challenge assumptions, indicating a productive exploration of the topic.

Contextual Notes

Participants note the need for careful consideration of definitions and conditions related to integrability and the behavior of functions at infinity. There is an acknowledgment of existing counterexamples that challenge initial assumptions.

Niles
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Homework Statement


HI all.

In order to perform a Fourier transform on a function f(x), f(x) must be integrable, i.e.

[tex] \int_{-\infty}^{\infty}|f(x)|dx < \infty.[/tex]

Can you confirm that this also implies that f(x) -> 0 for x -> (+/-) infinity?
 
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Can you find a function that has a finite area beneath it while not being zero in infinity?
 
Cyosis said:
Can you find a function that has a finite area beneath it while not being zero in infinity?

No. But I am wondering if it is a sufficient conditions for the integral to be finite? E.g. f(x) = x-1?
 
To avoid any confusion. Do you mean if f(x)->0 when x->+-infinity then the integral of f(x) over +- infinity converges? This is not true and you already gave a counter example. The function x^-1 goes to zero, but the integral of x^-1 from -infinity to infinity diverges.
 
Great, thanks!
 

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