Real Analysis: proving a sequence converges and finding its limit.

TeenieBopper
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Homework Statement


Suppose r>1. Prove the sequence \sqrt[n]{1 + r^{n}} converges and find its limit.


Homework Equations





The Attempt at a Solution



It's obvious that the sequence converges to r, so I know where I need to end up. My first instinct is to use the squeeze theorem. It's obvious that \sqrt[n]{r^{n}}<\sqrt[n]{1 + r^{n}}. However, I'm having difficulty finding a sequence that's greater than \sqrt[n]{1 + r^{n}} but also converges to r.
 
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TeenieBopper said:

Homework Statement


Suppose r>1. Prove the sequence \sqrt[n]{1 + r^{n}} converges and find its limit.


Homework Equations





The Attempt at a Solution



It's obvious that the sequence converges to r, so I know where I need to end up. My first instinct is to use the squeeze theorem. It's obvious that \sqrt[n]{r^{n}}<\sqrt[n]{1 + r^{n}}. However, I'm having difficulty finding a sequence that's greater than \sqrt[n]{1 + r^{n}} but also converges to r.
Try comparing to \displaystyle \sqrt[n]{2\,r^n}\ .
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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