Real component of the wavelength of microwaves in copper

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The discussion focuses on determining the real component of the wavelength of microwaves in copper, utilizing the relationship between the refractive index, relative permittivity, and conductivity. The equation provided indicates that the refractive index is influenced by the imaginary part due to copper's conductivity. It is noted that for microwaves, the imaginary component is significantly larger than the real part, making the latter less critical in this frequency range. As frequencies increase towards plasma resonance, the real part of the refractive index becomes more relevant. For accurate calculations, the Drude model for copper is recommended to simulate its behavior near plasma resonance.
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I am trying to work out the real component of the wavelength of microwaves in copper. I am given n2=er=-i sigma/eo omega

where n is the refactive index
er is the relative permitivity
eo is the permitivity of free space
i = sqrt(-1)
omega is the frequency of the microwave
sigma is the conductivity of copper

I was approaching this by using n=kc/omega where k is the wavenumber and then c=f*wavelength but I am not sure about obtaining the real part of the refractive index as the whole value is multiplied by i?

Any ideas or examples/links would be helpful.
 
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For microwaves it really doesn't matter as the imaginary part is much much larger than the real part. The real part does become more significant as we go above microwaves and approach the plasma resonance of the metal. If you really want to find the real part, I would suggest finding the Drude model for copper that simulates it as having a plasma resonance. I do not know off hand what the constants are for copper in the model.
 
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