Really a Question about Notation

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The discussion revolves around the negation of the statement that for all integers x greater than or equal to 1, the expression 5y² + 5y + 1 is prime. The provided negation states that there exists a y in the same set such that the expression is not prime, which is confirmed to be true with a counterexample. A question arises regarding the mixing of variables x and y in the notation, with suggestions for clarity in defining the set. It is proposed that expressing the statement using a defined set X for x could enhance understanding. The conversation emphasizes the importance of clear variable usage in mathematical notation.
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Homework Statement



Form negation and then either prove statement or negation:

\forally \in {x | x \in Z, x>=1}, 5y^2+5y+1 is a prime number.

The Attempt at a Solution



Answer given:

\existsy \in {x | x \in Z, x>=1} such that 5y^2+5y+1 is not prime.

The negation is true, counterexample follows.

My question is why are x,y mixed up?
 
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What do you mean why are x, y mixed up?
 
Well, there exists y belonging to a set where the elements are defined by x...

Would it be valid to express it as there exists x belonging to a set where the elements are defined by x... or the above the preferred way of doing it?
 
The way I interpret it is like this:

Let X be defined as the set of numbers \{x|x\in\mathbb{Z}, x\geq1\}.

Then:

\exists y \in X \text{ such that } 5y^2+5y+1 \text{ is not prime}

This might make it clearer that the set is being defined by the dummy variable x. It has no real purpose besides just being a dummy variable from what I can see.
 
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Very helpful thank you.
 
Atomised said:

Homework Statement



Form negation and then either prove statement or negation:

\forally \in {x | x \in Z, x>=1}, 5y^2+5y+1 is a prime number.

The Attempt at a Solution



Answer given:

\existsy \in {x | x \in Z, x>=1} such that 5y^2+5y+1 is not prime.

The negation is true, counterexample follows.

My question is why are x,y mixed up?

In plain English, the statement is: ##5 y^2 + 5y+1## is prime for any positive integer ##y##. Of course, as you have shown, the statement is false.
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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