Really basic question in ionic equilibrium

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The discussion focuses on two chemistry questions related to ionic equilibrium and electrochemical cells. For the first question about acetic acid, the key is to use the dissociation constant (Ka) to set up an equilibrium expression and find the H+ ion concentration. The second question involves identifying half reactions for an electrochemical cell with nickel and silver electrodes, where oxidation occurs at the anode and reduction at the cathode, utilizing standard reduction potentials (Eo). Participants emphasize the importance of understanding these concepts and encourage looking up examples for better comprehension. Overall, guidance is provided on how to approach these fundamental chemistry problems.
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Hello,
I am am working on my grade 12 chemistry course ALMOST DONE YEAHH!
I am stuck ona few questions, and I am hoping to get some help even if you just tell me where to begin on solving these.
1) If the Ka=1.8 * 10^{5} for acetic acid ( ie. CH_{3}COOH), what is the H^{+} ion concentration in a solution of this acid, if 1.2 grams of acid are dissolved in 1.0L of solution.
Is there a formula i should be using to solve this question I can't seem to figure out what I am supposed to be doing.

I know I am going ot get told, I have to show my work so far but that's just the problem I have no clue where to begin, so if someone could just help me with that, I am not asking for you to do the question for me.

2. An electrochemical cell is constructed by placing a nickel electrode into a 1.0 M NiSO_{4} solution, and a silver electrode into a 1.0 M AgNO_{3} solution, and then joining them with a salt bridge to complete the circuit.
a) give the anode half reaction and the E^{o} value.
b) give the cathode half reaction and the E^{o} value.
c) Give the net reactiona nd its E^{o} value.
What I am able to find out is The Eo value of Ag+ is +0.80 ans the Eo value of Ni2+ is -0.24> But other than this I am completely clueless as where to solve the question
PLEASE HELP!
 
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1)
This is a really basic question in ionic equilibirium. This is an example of dissociation of an acid in water.
Let me give you the general case.
Consider an acid HA which when dissolved in water partially ionizes into H+ and A- ions. There are H+ ions, A- ions and unionized HA in equilibirium in the solution.
Apply the http://www.science.uwaterloo.ca/~cchieh/cact/c123/massacti.html to this equilibirium.
You get,
K_a = \frac {[H+][A-]}{[HA]}

Where [H+], [A-], [HA] are the equilibirium concentrations and K_a is the dissociation constant of the acid HA.
Now, how do you find the H+ concentration from this?

You know the initial concentration of the acid because it is given in the question. Let the degree of dissociation of the acid be \alpha.

The degree of dissociation is a fraction of the total number of moles of an acid or base or electrolyte that dissociates into ions in an aqueous solution when equilibrium is reached.

Here, the total moles of the acid present initially is known. Call it as c
So, from the above definition, the number of moles of ions of H+ present is c\alpha. Similarly the number of moles of ions of A- present is also c\alpha.
So how many moles of unionized HA are present at equilibirium? From this, can you find the concentration of H+? Can you also post and show the general forumla to find the concentration of H+ and the value of alpha in terms of 'c' and 'Ka'?

Note: The value of Ka for Acetic acid is 1.8 x 10^(-5) and not 1.8 x 10^(+5)
 
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Hi there! It's great to hear that you're almost done with your chemistry course. Ionic equilibrium can be a tricky topic, but I'm sure with some guidance, you'll be able to solve these questions.

For the first question, you're given the Ka value for acetic acid and asked to find the H+ ion concentration in a solution. Remember that Ka is the equilibrium constant for the dissociation of an acid, so you'll need to set up an equilibrium expression using the formula for Ka. Then, you can plug in the given values and solve for the H+ ion concentration. If you're still stuck, try looking up examples or practice problems on Ka and acid dissociation to get a better understanding.

For the second question, you're dealing with electrochemical cells and half reactions. Remember that the anode is where oxidation occurs and the cathode is where reduction occurs. So, you'll need to identify which half reactions correspond to each electrode. The Eo value is the standard reduction potential, which you can find in a table. Once you have both half reactions and their Eo values, you can use them to calculate the net reaction and its Eo value. Again, if you're still unsure, try looking up examples or practice problems on electrochemical cells to get a better understanding.

I hope this helps you get started on these questions. Remember to always show your work and ask your teacher or classmates for help if you're still stuck. Keep up the good work and good luck with the rest of your course!
 
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