What is the value of e when substituting n=infinity into the limit (1 + 1/n)^n?
Thread startertahayassen
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In summary: Rewrite the right side as [ln (1 + 1/n)]/(1/n).Take the limit of both sides. If necessary, use L'Hopital's...I took the log of both sides, and then I moved the n exponent to the coefficient, so I got:logy = nlog(1+1/n)But I'm not sure where to proceed from here.This is the right track. Now you have an indeterminate form of the type [0/0] so you can use L'Hopital's rule. Taking the derivative of the top and bottom you get:d/dx(log(1+