Rearranging formulas. Accelerations

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SUMMARY

The discussion focuses on calculating average acceleration (Aav) using the formula Δd = viΔt + 1/2aavΔt^2. It emphasizes that this formula is applicable only under conditions of constant acceleration. The average acceleration is defined as the slope of a velocity-time graph, while the distance traveled corresponds to the area under the curve. A practical example illustrates that maintaining a constant speed after initial acceleration results in greater distance covered compared to a scenario with prolonged stationary time followed by acceleration.

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kencamarador
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If I were to solve for Aav

Δd = viΔt+1/2aavΔt^2

Vi- initial velocity
Aav is average acceleration
 
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No, that only works for constant acceleration. Consider a velocity-time graph. The average acceleration is the slope from the start point to finish point, while the distance traveled is the area under the curve. E.g. if you stayed put for an hour then accelerated at 10kph/s for 6 seconds you'd average 1 kph/minute but cover relatively little ground. Conversely, if accelerate for the first 6 seconds then maintain a 60kph an hour you'll have the same average acceleration but go much further.
 

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