How Does Current Direction Affect Force in a Rectangular Loop?

AI Thread Summary
The discussion focuses on calculating the magnetic forces acting on a rectangular loop of wire carrying a current in a magnetic field. The loop has dimensions of 4 cm by 5 cm and carries a current of 2.8 A in a uniform magnetic field of 3.8 × 10^-4 T. The user has successfully calculated the torque for the x-axis and y-axis but is struggling to determine the forces Fa and Fb for the z-axis. The formula F=I*L*B sin(theta) is provided to find these forces, but the user is encountering difficulties with the calculations. Assistance is sought to verify the values being used in the formula to resolve the issue.
ahazen
Messages
49
Reaction score
0
A rectanglular loop consists of 5 turns of wire carrying a current of 2.8 A. The loop is in the x-y plane, and the direction of flow of the current is shown in the figure. The loop has dimensions a = 4 cm and b = 5 cm. Consider a uniform magnetic field of strength 3.8 × 10-4 T in x, y, or z directions.

I need to find the:
-Fa on x-axis
-Fb on y-axis
-Fa on z-axis
-Fb on z-axis

For the X-axis, I found that torque is 1.064e-5 and Fb=0
For the y-axis, I found the torque is 1.064e-5 and Fa=0
I also found that the torque for z-axis is 0.

But, how do I find the other Fa and Fb?
I am given: F=I*L*B sin(theta)
 

Attachments

  • Torque.gif
    Torque.gif
    2.4 KB · Views: 608
Physics news on Phys.org
Hi ahazen,

ahazen said:
A rectanglular loop consists of 5 turns of wire carrying a current of 2.8 A. The loop is in the x-y plane, and the direction of flow of the current is shown in the figure. The loop has dimensions a = 4 cm and b = 5 cm. Consider a uniform magnetic field of strength 3.8 × 10-4 T in x, y, or z directions.

I need to find the:
-Fa on x-axis
-Fb on y-axis
-Fa on z-axis
-Fb on z-axis

For the X-axis, I found that torque is 1.064e-5 and Fb=0
For the y-axis, I found the torque is 1.064e-5 and Fa=0
I also found that the torque for z-axis is 0.

But, how do I find the other Fa and Fb?
I am given: F=I*L*B sin(theta)

By Fa, I assume you mean the magnitude of the magnetic force on side a due to the magnetic field, right? If so, then you have the formula; if you plug in your values (all you have to determine here is what theta is) what do you get?
 
yes, that's correct:) I'm still trying to work on the problem. Something is not working right when I plug the values in.
 
ahazen said:
yes, that's correct:) I'm still trying to work on the problem. Something is not working right when I plug the values in.

You seem to have the right formula; if you post the values you are plugging in and the result you get, I or someone else can try to verify it.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top