Recurring Equations: Solving for T(n) with Mathematical Induction

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Homework Statement



Solve the recurrence: T(n) = T(n/7) + T(4n/5) + n for n > 35 with base case T(n) = constant for n ≤ 35.

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The Attempt at a Solution



Is this mathematical induction? No idea how to do this one.
 
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You seem to be missing a "=". Where is it supposed to be?
 
Hi XodoX, it does look like a recurrence, except, as HallsofIvy is pointing, the recurrence rule is missing.
Is this T(n+1)=T(n)+T(n/7)+T(4n/5)+n ? (T(36)=3c+35)
if it is, what when n is not a multiple of 7 and 4n is not a multiple of 4 ? we take the floor / ceiling ? do you have some context around this question ?

Cheers...
 
Fixed it. Sorry, wrong button.
 
Still, is 36/7=5 ? is 144/5=28 ?
just to make sure we are solving the right problem, do you have some context around this puzzle ?

Cheers...
 
No, nothing else. So plug in numbers? But the equation does not hold up. I don't get it.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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