Red light to green light homework

AI Thread Summary
To determine the speed required for a vehicle to change a red traffic light to green, the discussion emphasizes using the Doppler shift formula, as the speed of light remains constant. Participants clarify that the frequency and wavelength of light do not change unless the source moves relative to the observer. The correct formula for calculating the Doppler effect is provided, but there is confusion regarding how to isolate the velocity (v) in the equation. Step-by-step algebraic manipulation is suggested to solve for v, highlighting the need for a solid understanding of the formula's components. Overall, the conversation revolves around applying relativistic principles to solve the problem accurately.
espania
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What speed would a vehical have to travel in order to red traffic light into a green traffic light?
i know that green light has wavelength of 5.40x10^-7 m
frequency of 5.56x10^14 hz

red light has wavelength of 6.60x10^-7 m
frequency of 4.54x10^14 hz

so do i use velocity = wavelenght x freq

for the 2 and then subtract the small from the large?
 
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No, the speed of light is always c, it doesn't depend on the frequency.
The only way to 'change' the frequency/wavelength is to approach or move away from the source.
Use the doppler shift formula and plug in the numbers. Take good note of what the numbers in the formula mean, so you won't confuse signs.
 
ok this is what i did.,

5.56 x 10^14 = (3x10^8 / 3x10^8 x v) 4.54 x 10^14

5.56 x 10^14 = (v) 4.54 x 10^14

so v = 1.2ms?
 
Nope.U need to open the book first and read the correct version of Doppler-Fizeau formulas...I think they mean the longitudinal effect...

Daniel.
 
is there one of you guys have grifftihs electrodynamics solution?:)please snd to my email
 
You can search the net for solutions,but i would't trust them,if i were you...

Daniel.
 
Ok where could I find or could anybody give me the formula for the doppler shift when traveling at speeds close to the speed of light.
So I need to take relativity into account.

I needs this as soon as possible, thanks.
 
The formula you should use is not in your book?

\frac{\lambda '}{\lambda}=\sqrt{\frac{c-v}{c+v}}
where \lambda ' is the Doppler-shifted wavelength and v is the relative velocity between source and observer (positive when approaching).

For v<<c, the approximation
\frac{\lambda&#039;}{\lambda}=1-\frac{v}{c}
will do.
 
I haven't a clue how to use this formula Galileo, because I am looking for v, and there are 2 v's in the equation.
Would you be able to explain how I do it, or do an eg. using different values.
I would really appreciate it. Thanks.
 
  • #10
EIRE2003 said:
I haven't a clue how to use this formula Galileo, because I am looking for v, and there are 2 v's in the equation.
Would you be able to explain how I do it, or do an eg. using different values.
I would really appreciate it. Thanks.
You'd have to solve the equation for v.

Show us how far you got. Obviously, you first have to square both sides of the equation to get rid of the square root. Then bring the numerator to the other side, and collect terms with v in it.
 
  • #11
I just don't know where to start. I ve never seen this formula before.
 
  • #12
How do I calculate v [the velocity of the car needed to turn red light to green light] from this equation ?? Please can somebody show me how?
 
  • #13
espania said:
How do I calculate v [the velocity of the car needed to turn red light to green light] from this equation ?? Please can somebody show me how?
Elementary algebra:

\frac{\lambda &#039;}{\lambda}=\sqrt{\frac{c-v}{c+v}} \Rightarrow<br /> \frac{\lambda&#039;^2}{\lambda^2}(c+v)=(c-v)<br /> \Rightarrow \frac{\lambda&#039;^2}{\lambda^2}c+\frac{\lambda&#039;^2}{\lambda^2}v+v=c

\Rightarrow (1+\frac{\lambda&#039;^2}{\lambda^2})v=c(1-\frac{\lambda&#039;^2}{\lambda^2}) \Rightarrow v=\frac{c(1-\frac{\lambda&#039;^2}{\lambda^2})}{(1+\frac{\lambda&#039;^2}{\lambda^2})}=\frac{c(\lambda^2-\lambda&#039;^2)}{(\lambda^2+\lambda&#039;^2)}
 
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