Reduce the amount of kinetic energy loss in a collision

AI Thread Summary
To reduce kinetic energy loss in a marble collision, using tubes as a track can minimize friction and ensure a direct impact. Strategies to eliminate energy loss to sound and heat include using materials like rubber between the marbles, although this may increase friction. Introducing a third marble between the colliding marbles could help reverse backspin and enhance energy transfer. The goal is to maximize energy transfer to the second marble rather than retaining it in the first. Overall, optimizing the collision setup is key to achieving better energy conservation.
fdajkffk
Messages
14
Reaction score
0
I have a lab in which a moving marble collides with a still one. What changes could I make to reduce the amount of kinetic energy loss in the collision? The track for the marbles is a piece of card stock paper.


I was thinking:
-Use two tubes as a track which will reduce the amount of friction on the marble and prevent a glancing collision.

How would I eliminate energy loss to sound and heat? Any ideas?
Any other ideas for reducing ek loss as well?
 
Physics news on Phys.org
I assume that the objective is to transfer as much energy as possible to the second marble, rather than to minimise the energy lost. I.e., you don't care about energy retained by the first marble. So yes, ensuring the collision is head-on is good.
Would it be possible to put something between the marbles? E.g. a thin piece of rubber, maybe from a superball? The downside of that is the high friction, so you might need another (hard) layer either side of the rubber with low friction.
Another possibility is to put a third marble in between, touching the stationary one. The theory behind this is that when a rolling ball strikes a stationary one it tends to impart backspin. The extra marble in the middle will reverse the spin.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top