Reducing Sqrt(4t^2+4+1/t^2): Calculus Problem Help

AI Thread Summary
To reduce sqrt(4t^2 + 4 + 1/t^2) to (1 + 2t^2)/t, first factor out 1/t^2, leading to (4t^4 + 4t^2 + 1)/t^2. Recognize that 4t^4 + 4t^2 + 1 can be expressed as (2t^2 + 1)^2. This allows for simplification under a single fraction. Ultimately, taking the square root yields the desired result of (1 + 2t^2)/t.
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reducing sqrt(4t^2+4+1/t^2) to (1+2t^2)/t




The Attempt at a Solution


- This is actually just a portion of a calculus problem, but I can't figure out how the book did the algebra here. I get (2t^2+2t+1)/t and don't know how that reduces to (1+2t^2)/t. Please help.
 
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Factor the 1/t^2 out as 1/t. Then 4*t^4+4*t^2+1=(2*t^2+1)^2.
 
Put the whole thing under a single fraction : (4t^4 + 4t^2 + 1) / t^2
Now above you have a complete square so you can simplify this and when you do the square root you get the exact solution
 
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