Reduction Gearbox Calculation question

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Discussion Overview

The discussion revolves around the calculation of torque required to turn the output shaft of a 500:1 reduction gearbox when the torque needed for the input shaft is known. Participants explore the implications of reversing the gearbox's function and the effects of friction on the calculations.

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant questions whether the torque required to turn the output shaft can be calculated by simply multiplying the input shaft torque by the gearbox ratio of 500:1.
  • Another participant asserts that this approach is not valid for a high ratio like 500:1, implying that additional factors must be considered.
  • A further response highlights the complexity introduced by friction loading, noting that bearing friction and gear tooth contact friction will be multiplied at each stage of the gearbox.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method for calculating the output shaft torque, indicating that multiple competing views remain regarding the effects of gearbox ratio and friction.

Contextual Notes

The discussion does not resolve the mathematical steps needed for the calculation and does not clarify the specific assumptions regarding friction and load conditions.

UrSleyeNess
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If Have have the torque needed to turn the input shaft of a 500:1 Gearbox with no load, can that information allow me to calculate the opposite. I want to know the torque required to turn the output shaft.

What I mean is, if you were to apply the force to the output shaft. In other words, use a Reduction gearbox in reverse.

This has been driving me nut to figure out if it is as simple as taking the torque required to turn the input shaft and multiply it by 500 since I am talking a 500:1 ratio...

Reply here if you know or email me directly at <email address deleted by Moderator>

Thanks
Chris
 
Last edited by a moderator:
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UrSleyeNess said:
This has been driving me nut to figure out if it is as simple as taking the torque required to turn the input shaft and multiply it by 500 since I am talking a 500:1 ratio...

No - not for a ratio as high as 500:1 .
 
Nidum said:
No - not for a ratio as high as 500:1 .

If not then why and how would I calculate it?
 
The difficulty is that the friction loading due to any bearing friction and any contact friction between the gear teeth is going to be multiplied at each stage as well.
 

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