Reference framefrom masteringphysics

Click For Summary
SUMMARY

The discussion centers on calculating Shawn's speed relative to Susan's reference frame using vector addition. The formula provided is \(\vec{v}_{(Shawn/Susan)} = \vec{v}_{(Shawn/Ground)} - \vec{v}_{(Susan/Ground)}\). Susan is driving north at 60 mph, while Shawn is driving east at 45 mph. Participants are encouraged to express the velocities in component form to solve the problem effectively.

PREREQUISITES
  • Understanding of vector addition and subtraction
  • Familiarity with reference frames in physics
  • Knowledge of component form representation of vectors
  • Basic principles of relative motion
NEXT STEPS
  • Study vector addition in physics
  • Learn about reference frames and their applications
  • Explore component form of vectors in detail
  • Practice problems involving relative velocity
USEFUL FOR

Students studying physics, particularly those preparing for AP exams, and educators looking for examples of relative motion and vector analysis.

xyoonboixkpx
Messages
4
Reaction score
0
This is the only problem taht i could not figure out for 2 hours...
I even asked one of my friend who got 5 on his ap exam about this problem..he said no no to this question..anybody willin to help?

.Susan, driving north at 60 mph, and Shawn, driving east at 45 mph, are approaching an intersection

Q: What is Shawn's speed relative to Susan's reference frame?
 
Physics news on Phys.org
Try this:
\vec{v}_{(Shawn/Susan)} = \vec{v}_{(Shawn/Ground)} + \vec{v}_{(Ground/Susan)} = \vec{v}_{(Shawn/Ground)} - \vec{v}_{(Susan/Ground)}

Hint: Write the vectors in component form.
 
thanks for da help
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
20K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
28K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
4
Views
8K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K