Refrigeration theory: Why does the compression follow an isentrope?

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In an ideal scenario, a perfect compressor follows an isentropic path during compression, indicating a reversible and adiabatic process where no heat is transferred. However, real compressors exhibit an isentropic efficiency of around 0.8 due to factors like fluid friction and interactions between the piston and cylinder wall, which introduce irreversibility and deviate from the isentropic line. The ideal compression process assumes no heat generation or losses, resulting in zero entropy change, which aligns with the second law of thermodynamics. In practical applications, the compression process does lead to an increase in refrigerant temperature and pressure. Understanding these principles is crucial for optimizing refrigeration systems.
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When you have a perfect compressor the compression will follow an isentropic line and an h,log(p)-diragram (enthalpy,pressure diagram) but why? What is entropy exactly and what does it mean in such a system?

In real life the compressors have an isentropic efficiency of maybe 0.8, which will make the compression on the diagram deviate from the isentropic path. But why? Is it just because the friction etc. in the compressor heats up the refrigerant?
 
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Hey I do not think that it does.
 
Compression process is isentropic(ideally),isentropic means that process is entirely reversible and adiabetic.
adiabetic means no heat transfer,this can be achieved via proper insulation etc.now coming to the irreversibility,fluid friction and friction between the cylinder wall and Piston are the causes of irreversibility that causes a compressor to deviate from isentropic path..
why compressor should follow isentropic path? ans: "ideally" compressor is not generating any heat,no losses at all,all the energy given to compressor is transferred to fluid.therefore,entropy change is zero(which violates the 2nd law of thermodynamics)
compressor heats up the refrigerant? and: yes,in comprsr with pressure,temp of ref also increases.
 
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