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Regarding quantum physics(fermi energy)

  1. May 2, 2009 #1
    The average electron energy in an electron gas is known to be <e>=3E(f)/5. The energy for N such electrons would be 3NE(f)/5. Find the pressure in terms of U and V, where V is the volume of the electron gas.

    My solution.

    Fermi energy
    E(f)=(h^2/2m)*((3N/8*pie*V)^(2/3))
    therefore E(F) is proportional to V^(-2/3)
    since it is proportional i just have to plug into 3NE(f)/5 or the other one correct?

    Thanks.




    so which formula do i plug V^(-2/3) into E(F)? The 3NE(f)/5 or 3E(f)/5.
     
  2. jcsd
  3. May 2, 2009 #2
    Hah, you have me confused. Lets write down what you have:

    [tex]U=(3/5)NE_F[/tex]
    and
    [tex]E_F = C V^{-2/3}[/tex]

    where I stuck all those nasty constants that don't depend on V in the term C.

    So, you also know [tex]P=-dU/dV[/tex].

    You have all the pieces, just put them together now.
     
  4. May 2, 2009 #3
    but the pressure needs to be in terms of U and V.
     
  5. May 2, 2009 #4
    First use substitution to remove the Fermi energy from the first equation. Then take the derivative with respect to V. And substitute back in U to get the pressure in terms of U and V.
     
  6. May 3, 2009 #5
    thanks.
     
  7. May 3, 2009 #6
    after i take derivative i have p=-dU/dV=(6/15)NC*(V^(-5/3))
    you can't substitue this into U because it isn't=U to derivative of du/dv.
     
  8. May 3, 2009 #7
    First, 6/15 can be simplified. Second, you can pull a U out of that final equation of yours. Just remember what U is equal to, and factor that out of the equation above, and then make it U.
     
  9. May 3, 2009 #8
    Can i do this U=3/5*N*C*(V^(-2/3)). so solve for N and plug into p=-dU/dV=(6/15)NC*(V^(-5/3))? don't really understand what you mean by pull out U from -du/dv.
     
  10. May 3, 2009 #9
    You can do that as well, or even solve for C and plug it in. All the constants will cancel out in the end and you will be left with U and V for your pressure equation.
     
  11. May 3, 2009 #10
    thank you so much.
     
  12. May 3, 2009 #11
    now he asks to find bulk modulus. B=-V*(dp/dv) but he wants it in terms on U only and if i take derivative and simplify i am left with 2U/3V again but am unsure of how to get further in terms of plugging in for V.
     
  13. May 3, 2009 #12
    You need to show some work. And remember that U also depends on V.
     
  14. May 3, 2009 #13
    so use U=(3/5*N*C*V^(-2/3)) solve for V and substitute?
     
  15. May 3, 2009 #14
    here's what i did B=-V(dp/dv)=-V((d/dV(2U/3V))=2U/3V. But i need my answer in terms of of only U.
     
  16. May 3, 2009 #15
    You didn't take the derivative of U with respect to V in that formula. But that formula may not be the best to take the derivative of. Try a formula you quoted earlier...

    Take the derivative of that pressure with respect to volume, then substitute the U back in.

    Edit: Nevermind, I see your problem. What does the problem ask for exactly?
     
    Last edited: May 3, 2009
  17. May 3, 2009 #16
    Problem:
    The bulk modulus, B, is defined to be B=-V(dp/dv). Find expression of B in terms of U.
     
  18. May 3, 2009 #17
    Well, I get a similar answer as with the U/V, except I get a different coefficient than you. But I still also get the volume in my bulk modulus. So not sure how to express it only as U.
     
  19. May 3, 2009 #18
    thanks for help i will just ask teacher tom.
     
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