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My solution.

Fermi energy

E(f)=(h^2/2m)*((3N/8*pie*V)^(2/3))

therefore E(F) is proportional to V^(-2/3)

since it is proportional i just have to plug into 3NE(f)/5 or the other one correct?

Thanks.

so which formula do i plug V^(-2/3) into E(F)? The 3NE(f)/5 or 3E(f)/5.