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Relation between coherent and Fock states of light

  1. Sep 24, 2011 #1
    Hi.

    Coherent states of light, which correspond to classical em wave, are eigenstates of non-Hermite annihilation operator. Fock states are eigenstates of Hermite number operator. Are Fock states are expressed by combination of coherent states? If yes, how?

    Thank you in advance.

    ref. https://www.physicsforums.com/showthread.php?t=530937
     
  2. jcsd
  3. Sep 25, 2011 #2

    Bill_K

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    Science Advisor

    Look for the Wikipedia page "Coherent States", and on that page search for "representation"
     
  4. Sep 25, 2011 #3

    Dale

    Staff: Mentor

    Hi Bill, on that page:
    http://en.wikipedia.org/wiki/Coherent_states

    It describes decomposing a coherent state as a superposition of Fock states, but as far as I can tell it doesn't describe the other way around, decomposing a Fock state as a superposition of coherent states. Do you know if that is possible?
     
  5. Sep 25, 2011 #4
    The decomposition of any state (pure or mixed) into superposition of coherent states was the central result of the coherent states formalism (follow up on Glauber-Sudarshan P representation in that wiki article). Note also that the coherent states are not mutually orthogonal (since anihilation operator is not Hermitean) and that they form over-complete basis, hence the decomposition of arbitrary field state into coherent states is not unique (thus, there are other decompositions besides the canonical G-S P representation).
     
  6. Sep 25, 2011 #5
    Hi, nightlight. Thanks for your teaching.

    From formula in Wiki |α> = e^(-|α|^2 /2) ( |0> + α|1> + ... ) disregarding higher orders of α for |α|<<1
    |α> = |0> + α|1> so coherent state of very weak light is superposition of almost vaccuum and small poriton linear to α of one photon Fock state, I think.

    Though coherent states are eigenstates of non Hermitian annihilation operators, why we can regard them corresponding to classical em wave ? I believe only observables, i.e. Herimite operators, should have classical correspondents. Am I wrong?

    May I write Fock state |0>=D^-1(α)|α> where |α> is coherent state and D(α)=exp(α a+ - α* a) or D^-1(α)=exp(|α|^2/2)exp( - α a+) ?
    Though I do not know the way of practical calculation.

    Regards.
     
    Last edited: Sep 26, 2011
  7. Sep 26, 2011 #6

    tom.stoer

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    The idea is to prove something like

    [itex]1 = c\, \int_\mathbb{C}dz\,d\bar{z}\,|z\rangle\langle z|[/itex]

    and to express the coherent states in terms of Fock states.

    Using

    [itex]z^n = r^n\,e^{in\phi}[/itex]

    one can rewrite the integral and use the phi-integration

    [itex]\int_0^{2\pi} d\phi\,e^{i(m-n)\phi} = \delta_{mn}[/itex]
     
    Last edited: Sep 26, 2011
  8. Sep 26, 2011 #7
    The "classicality" here means that the joint probabilities of photon counts at spacelike points factorizes (just as it would do if for the classical EM field). The largest class of "classical" states in that sense consists of all superpositions of coherent states with positive, non-singular P(alpha).

    In the coherent state decomposition the vaccum state |0> uses displacement operator D(0). For calculations and usefulness of coherent state representation, check the original Glabuer's papers (from early 1960s) or a good QO textbook, e.g. chap 11 in L. Mandel, E. Wolf "Optical Coherence and Quantum Optics" Cambridge Univ. Press., 1995.
     
  9. Sep 26, 2011 #8

    DrChinese

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    Gold Member

    Haven't seen your name in a while... welcome back. :smile:

    -DrC
     
  10. Sep 27, 2011 #9
    Oh, I drop by here every few days. But I am way too busy with my day job to join discussions.
     
  11. Sep 29, 2011 #10

    Dale

    Staff: Mentor

    Thanks, that is what I needed.
     
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