Relation between 'P' and 'V' for an Adiabatic process

Click For Summary
SUMMARY

The discussion focuses on the derivation of the equation PVγ = constant for adiabatic processes, utilizing the first law of thermodynamics. It highlights the substitution of internal energy from an isochoric process into an adiabatic context, establishing that the heat absorbed during isochoric processes is not equivalent to work done in adiabatic processes. The significance of the heat capacity ratio (γ) is also examined, revealing its dependence on the degrees of freedom of gas molecules, with values of 1.67 for monoatomic gases and 1.4 for diatomic gases. This ratio is crucial for understanding the efficiency of cyclic processes in thermodynamic systems.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with concepts of internal energy and work in thermodynamics
  • Knowledge of heat capacity (Cv and Cp) and their definitions
  • Basic principles of adiabatic and isochoric processes
NEXT STEPS
  • Study the derivation of the first law of thermodynamics in detail
  • Explore the implications of the heat capacity ratio (γ) in cyclic processes
  • Investigate the relationship between degrees of freedom and heat capacity for various gases
  • Learn about real-world applications of adiabatic processes in thermodynamic cycles, such as Carnot engines
USEFUL FOR

Students of thermodynamics, physicists, engineers, and anyone interested in the principles governing adiabatic processes and their applications in heat engines.

Dr. Who
Messages
9
Reaction score
0
Hi All,

I have a little query concerning the derivation of PV γ = constant. In my textbook of Physics, first they give the equation for adiabatic process using the first law of Thermodynamics, as;

dEint = W → (1)​

where,
ΔEint ⇒ change in internal energy and W ⇒ workdone
Then, they used the relation:

Cv = Q / ndt​
Where,
Q ⇒ heat
'n' ⇒ no. of moles
Cv ⇒ Molar Heat capacity at constant volume
dT ⇒ Change in temperature

Now, for an isochoric process;
Q = dEint
dEint = nCvdT → (2)​

Substituting dEint from eq.(2) into eq.(1)

⇒ W = nCvdT​

As thermodynamic work is given as W = -PdV
∴ -PdV = nCvdT
⇒ PdV = - nCvdT → (3)​

Now, writing equation of state of the gas in differential form as;
d(PV) = d(nRT)​
⇒ PdV + VdP = nRdT​
Using eq.(3)
⇒ - nCvdT + VdP = nRdT
⇒ VdP = nCvdT + nRdT​

Using the relation Cp = Cv + R into the above equation

⇒ VdP = nCpdT → (4)​

Now, dividing eq.(4) by eq.(3)
⇒ VdP / PdV = -Cp / Cv
or VdP / PdV = -γ
where, γ ⇒ ratio of molar heat capacities

Rearranging the above equation:
dP / P = -γ dV / V​
Integrating both sides with the initial state 'i' and final state 'f' being the lower and upper limits respectively, gives;

dP / P = -γ dV / V​

⇒ PiViγ = PfVfγ

which can be written as: PV γ = constant

Now, my query was that,
1. why have they substituted the internal energy from an isochoric process into an adiabatic process (Substituting dEint from eq.(2) into eq.(1))? Considering this substitution, can we say that heat absorbed in the isochoric process is equivalent to the work done in an adiabatic process?

2. What is the physical significance of γ on a curve of PV γ = constant ? (Please do not go into the details of poltropic processes)
 
Science news on Phys.org
Dr. Who said:
1. why have they substituted the internal energy from an isochoric process into an adiabatic process (Substituting dEint from eq.(2) into eq.(1))? Considering this substitution, can we say that heat absorbed in the isochoric process is equivalent to the work done in an adiabatic process?

2. What is the physical significance of γ on a curve of PV γ = constant ? (Please do not go into the details of poltropic processes)
For an isochoric process the work done is always zero.
A typical example of an isochoric process is addition or removal of heat from a closed system.
The volume remains constant but temperature and pressure change according to the process.
thus leading to change in internal energy.

An adiabatic system is perfectly insulated from external environment and there is no heat transfer in or out of the system.
Work done in an adiabatic process completely results in change in the internal energy of the system.
so the two processes can be related.The heat capacity ratio(gamma) for an ideal gas can be related to the degrees of freedom of a molecule of gas

gamma = 1 + 2/(degree of freedom )
for a monoatomic gas, degree of freedom is 3 so its value is (1 +2/3) = 1.67
and for diatomic gas it (gamma) goes to 1.4 as the gas has five degrees of freedom.
This ratio becomes important when one uses the gas in a cyclic process for conversion of heat into work. and gas is taken as working substance like in a heat ( carnot engine.) engine.
 
  • Like
Likes   Reactions: Dr. Who

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
9
Views
3K