Relation for Inner Product with States from a Complete Set

[tommy01]

Hi.

I've found the following relation (in a book about the qm 3-body scattering theory):

<\Omega^{\pm}^{\dagger} \Psi_n|p>= ... = 0

where |p> is a momentum eigenstate.
So it is shown, that the inner Product is zero. Then they conclude that \Omega^{\pm}^{\dagger}|\Psi_n> = 0 because the p-states form a complete set.

How can this formally be shown?

thanky you.

 

[George Jones]

First, something a little more general.

How is a ket \left| \psi \right> expressed with respect to the complete set of states \left| p \right>?

 

[tommy01]

This isn't mentioned in the book. But i assume |\Psi>=\int |\mathbf{p}><\mathbf{p}|\Psi> d\mathbf{p} as usual. Or what you mean?
thanks for the quick reply.

 

[George Jones]

This isn't mentioned in the book. But i assume |\Psi>=\int |\mathbf{p}><\mathbf{p}|\Psi> d\mathbf{p} as usual. Or what you mean?
thanks for the quick reply.

Yes.

Now, what is the only possibility for |\Psi> if <\mathbf{p}|\Psi> is zero for every \mathbf{p}?

 

[tommy01]

thanks a lot.