Relationship between changing a wire's diameter and change in temp

AI Thread Summary
The discussion centers on the relationship between the diameter of nichrome wire and the temperature change of submerged water over five minutes. It establishes that resistance is inversely proportional to the diameter squared, leading to the conclusion that temperature change (ΔT) is proportional to the diameter squared as well. The analysis incorporates Joule's law and the concept of power, emphasizing that with constant voltage, the energy transferred to the water is related to the wire's diameter. The final conclusion is that the actual temperature change is proportional to the square of the diameter, highlighting the mathematical relationship between these variables. Understanding this relationship is crucial for predicting temperature changes in practical applications.
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Homework Statement



Hello! I have a problem where I need to develop and justify a hypothesis surrounding the relationship between the thickness (or diameter) of a nichrome wire and the temperature of water that it's submersed in over a time of 5 minutes. (proportionality statement and equations)

Homework Equations



So far, I know that resistance is inversely proportional to cross-sectional area, and therefore:
R ∝ 1/A
R ∝ 1/∏r^2
R ∝ 1/∏(d/2)^2
and because 2 and ∏ are constant
R ∝ 1/d^2 (resistance is inversely proportional to diameter squared) (I think!)

Now, I've also researched Joule's law, which eventuates into:
Heat produced = Pt = VIt = V^2/Rt = I^2Rt

The Attempt at a Solution



Now, I'm trying to get a relationship between diameter and ΔT, and I thought, so I have R ∝ 1/d^2, and P = V^2/R where V is a constant so P ∝ 1/R
and since P is the change in heat:
ΔT ∝ 1/RORsince thickness makes resistance go down
and less resistance makes ΔT (somehow)
then is R ∝ ΔT
and substituting so therefore:
ΔT ∝ 1/d

and I don't have much idea how to reason out what the graph will look like/why...

I think I've tied myself in knots... any help would be much appreciated! Thank you!:)
 
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I think you have to assume the wire is connected to a constant voltage source and I'd also ignore any change in resistance of the wire with temperature.

Therefore your approach is correct..

R ∝ 1/∏(d/2)2
R ∝ 1/d2

Then use..

Power = V2/R

Power = V2 * d2........(1)

If the water is in an insulated container then the energy it contains (E) is given by

E = Specific heat capacity * mass * Δ Temperature

Rearrange to give..

Δ Temperature = E / Specific heat capacity * mass

Then..

E = Power * Time

so

Δ Temperature = Power * Time / Specific heat capacity * mass ...(2)

Put (1) into (2)...

Δ Temperature = V2 * d2 * Time / Specific heat capacity * mass

Voltage, Time, Specific heat capacity and mass are all constant so

Δ Temperature ∝ d2

eg The change in temperature over 5min (not the actual temperature) is proportional to d2

Temperature = Initial Temperature + Δ Temperature

So actual temperature is proportional (but not directly proportional) to d2.

http://en.wikipedia.org/wiki/Proportionality_(mathematics )
 
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