Relationship between Frequency and Volume in Blowing Air into a Bottle

  • Thread starter Thread starter mtr
  • Start date Start date
  • Tags Tags
    Air
AI Thread Summary
The discussion centers on the relationship between the frequency of sound produced by blowing into a water-filled bottle and the volume of water in the bottle. Participants analyze the formula f=f_{0}(\frac{V}{V_{0}})^{\alpha}, questioning its validity, particularly when V=0, as frequency should not equal zero in that case. They clarify that the wavelength is inversely proportional to the height of the air column, which affects the frequency. The conversation also touches on the bottle's shape and how it influences the sound produced, suggesting that treating the bottle as a cylinder may yield different results. Ultimately, the original formula is deemed not to accurately represent the relationship between frequency and volume.
mtr
Messages
21
Reaction score
0

Homework Statement


There is a plastic bottle into which we blow in such a way, that we receive a sound of freguency f. The bottle is filled with water that has volume V. Prove, that f=f_{0}(\frac{V}{V_{0}})^{\alpha}, where f_{0}, V_{0}, \alpha are constants.

Homework Equations



The Attempt at a Solution


I always thought, that the wavelength is directly proportional to height of an empty part of the bottle, but then f is inversely proportional to V. Is there any mistake in this task?
 
Physics news on Phys.org
Hi mtr,

mtr said:

Homework Statement


There is a plastic bottle into which we blow in such a way, that we receive a sound of freguency f. The bottle is filled with water that has volume V. Prove, that f=f_{0}(\frac{V}{V_{0}})^{\alpha}, where f_{0}, V_{0}, \alpha are constants.

Homework Equations



The Attempt at a Solution


I always thought, that the wavelength is directly proportional to height of an empty part of the bottle,

As the height of the air space decreases, the wavelength will decrease also.

but then f is inversely proportional to V.

What is your reasoning for saying that?
 
alphysicist said:
As the height of the air space decreases, the wavelength will decrease also.

That's right, but considering the wavelength, we know, that \lambda = 2L so when L decreases, lambda decreases proportionally to the 1st power of L and inversely proportionally to the 1st power of V.


alphysicist said:
What is your reasoning for saying that?

I can see my mistake. In fact it is lambda inversly proportional to V so f is directly proportional to V.

Still, I made an experiment and it looks like there is such a formula: f=f_{0} \alpha^{\frac{V}{V_{0}}}
Actually I'm even more confused with this. Still the formula given in the task cannot be correct, because when V=0, f does NOT equal 0.
 
mtr said:
That's right, but considering the wavelength, we know, that \lambda = 2L so when L decreases, lambda decreases proportionally to the 1st power of L and inversely proportionally to the 1st power of V.

Think of the bottle as a cylinder. This would be like a pipe with one end closed, so the fundamental wavelength is 4L, if L is the height of the air column.

But I don't think the wavelength is inversely proportional to V, as you've seen when you looked at the frequency. As V increases, the wavelength decreases, but not proportionally.




I can see my mistake. In fact it is lambda inversly proportional to V so f is directly proportional to V.

Still, I made an experiment and it looks like there is such a formula: f=f_{0} \alpha^{\frac{V}{V_{0}}}
Actually I'm even more confused with this. Still the formula given in the task cannot be correct, because when V=0, f does NOT equal 0.

Was the problem that you had in the original post all that there was? There were no diagrams, or approximate ranges given? By treating the bottle as a cylinder you can get an exact result, which does not match with f\propto V^{\alpha} from your original post.

If I'm reading the problem correctly, and you haven't overlooked any parts of the problem in your post, then I would agree that the formula in the original post does not seem to be an exact answer.
 
alphysicist said:
But I don't think the wavelength is inversely proportional to V, as you've seen when you looked at the frequency. As V increases, the wavelength decreases, but not proportionally.

Well, I won't argue with that ;)


There were no additional information. They also do not say anything about the bottle's shape, so I suppose it can be any.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top