Relationship of simple pendulum

AI Thread Summary
The discussion focuses on the relationship between angular frequency (ω) and periodic time (T) in the context of a simple pendulum. It is established that ω = 2π/T, which indicates that angular frequency is inversely proportional to the period. Additionally, T can be expressed as T = 2π√(l/g), linking the period to the pendulum's length and gravitational acceleration. The presence of 2π in both equations highlights a consistent relationship between these variables. Understanding these equations is essential for accurately defining the motion of a simple pendulum.
joelKID984
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hi guys,

I'm currently working on a physics report about a simple pendulum and can't figure out how to answer one of the questions:

3. "define all terms in the solution(x(t)=Acos(ωt)) and especially the relationship between angular frequency, and periodic time, T."

ive defined all the terms, A is amplitude, ω is angular frequency etc. but have no clue of the relationship between angular frequency, and periodic time?

I know that ω=2∏/T = 2∏f

and

T=2∏√l/g

but don't get their relationship?

any help will be great.

cheers,
Joel C.
 
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joelKID984 said:
I know that ω=2∏/T = 2∏f

This is your relationship here.

The other formula you gave just gives the periodic time as a function of length.
 
Thanks mate.

So I something like "it can be established that the relationship between angular frequency and period time is:

ω=2∏f"

Do I say anything else? There is 2∏ in both equations, is that some sort of relationship?

Cheers,
Joel
 
joelKID984 said:
Thanks mate.

So I something like "it can be established that the relationship between angular frequency and period time is:

ω=2∏f"

Do I say anything else? There is 2∏ in both equations, is that some sort of relationship?

Cheers,
Joel

The only other relation would be T=2π√(l/g), but generally you can leave it as that.

In the derivation for the periodic time, you get to a point where ω2= g/l and that ω=2π/T as per its definition.
 
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