Relative Motion: Calculating the Angle for Accurate Newspaper Delivery

AI Thread Summary
The newspaper boy must calculate the angle to throw the papers to hit the porches while riding at a speed of 4m/s and throwing at 6m/s horizontally. The horizontal throw speed is relative to the boy, not the sidewalk, which complicates the triangle formed in the motion analysis. The hypotenuse of the triangle represents the throw speed at the angle, while the horizontal component corresponds to the effective speed relative to the sidewalk. Understanding the relationship between the speeds and the angle is crucial for accurate delivery. The discussion emphasizes the need to apply trigonometric principles to resolve the velocities correctly.
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Homework Statement



Homework Statement


A newspaper boy throws papers sideways onto the porches of his customers while riding his bicycle along the sidewalk. The sidewalk is 15m in front of the porches. The boy throws the papers at a horizontal speed of 6m/s relative to himself, and rides the bicycle at a speed of 4m/s relative to the sidewalk.
Question: If he waits until he is directly opposite a porch, at what horizontal angle with respect to the sidewalk will he have to throw the paper to hit the porch?

Homework Equations



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The Attempt at a Solution


Here is the triangle I'm supposed to get, but what I don't get is why is the hypoteneuse of the triangle 6m/s, when that is the horizontal speed, shouldn't the horizontal line of the triangle be 6?

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Who said that triangle has to be like that? I also understood from the question that 6m/s should be on the X the other side, not the hyp.
And thus hypotenuse would be derived from pythagoras theorem
 
He is not throwing the newspaper straight sideways from himself, but back at an angle. Yet the speed relative to the boy is 6m/s, so that is 6m/s at the perceived angle. To a bystander, the paper does travel perpendicularly to the boy's path. (But at some other speed.)
 
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