- #1
jasonchiang97
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Homework Statement
In an action-adventure film, the hero is supposed to throw a grenade from his car, which is going 79.0 km/h , to his enemy's car, which is going 125 km/h . The enemy's car is 15.9 m in front of the hero's when he let's go of the grenade.
If the hero throws the grenade so its initial velocity relative to him is at an angle of 45 ∘ above the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance.
Homework Equations
Vx=Vcos45°*
Vy=Vsin45°
x=-b√(b2-4ac)/2a
d-vyt+gt2/2
Rx=Vcos45*t
The Attempt at a Solution
villain velocity in m/s=34.72
hero velocity in m/s=21.94
34.72-21.94=8.77m/s
Vx/cos45=V
Vy=(Vx/cos45)sin45
d=(Vx/tan45)t+gt2/2Not sure what to do now.