1. The problem statement, all variables and given/known data In an action-adventure film, the hero is supposed to throw a grenade from his car, which is going 79.0 km/h , to his enemy's car, which is going 125 km/h . The enemy's car is 15.9 m in front of the hero's when he lets go of the grenade. If the hero throws the grenade so its initial velocity relative to him is at an angle of 45 ∘ above the horizontal, what should the magnitude of the initial velocity be? The cars are both traveling in the same direction on a level road. You can ignore air resistance. 2. Relevant equations Vx=Vcos45°* Vy=Vsin45° x=-b√(b2-4ac)/2a d-vyt+gt2/2 Rx=Vcos45*t 3. The attempt at a solution villain velocity in m/s=34.72 hero velocity in m/s=21.94 34.72-21.94=8.77m/s Vx/cos45=V Vy=(Vx/cos45)sin45 d=(Vx/tan45)t+gt2/2 Not sure what to do now.