Relative Velocity of walking

1. Oct 16, 2005

Jacobpm64

You exercise by walking for 15 minutes on a treadmill that has a level track that moves at a velocity of -4km/h.

What is your velocity relative to the floor?

What is your total displacement relative to the treadmill when you finish exercising?

What is your total displacement relative to the floor when you finish exercising?

2. Oct 16, 2005

Integral

Staff Emeritus
At least make some guesses of your own. Can you show us that you have put some thought into the problem?

3. Oct 16, 2005

Jacobpm64

i can try..

I think this one would be +4km/h. Hard for me to explain why i think this, but I'll try. Uhmm the treadmill is moving backwards.. and you have to run forwards at the same speed as the treadmill so that you won't fly off the treadmill in either direction (run too slow.. and you fall off the back end.. run too fast and you fall off the front).. So, if you run at the same speed as the treadmill, but in an opposite direction, you will end up staying in one place (which is the object of the treadmill)... So, your velocity relative to the treadmill would be +4km/h? I don't know.. but that's what i think

What is your velocity relative to the floor?
Since you aren't actually moving anywhere, the velocity relative to the floor is 0km/h? I think..

What is your total displacement relative to the treadmill when you finish exercising?
Because I said the velocity that i move relative to the treadmill is +4 km/h, then to find the displacement, I can solve for displacement in the velocity formula (v = d/t), to get d = vt. Plugging in the numbers, I get 15 min x 4km/h.. convert hours to minutes... 15min x 1/15 km/min = +1 km
So, my answer is +1 km.

What is your total displacement relative to the floor when you finish exercising?
Same approach, using the answer from the 2nd question this time... d = vt... So, plugging in numbers, 15min x 0km/min = 0km