Relativistic velocity transformations

AI Thread Summary
The discussion revolves around calculating the speed of a gamma ray emitted from a krypton-80 nucleus moving at 0.60c relative to the sun, using relativistic velocity transformations. For part a, the calculation confirms that the gamma ray travels at the speed of light (1c) relative to the sun, aligning with the postulate of relativity that light's speed is constant for all observers. In part b, there is uncertainty about how to approach the calculation when the gamma ray is emitted opposite to the nucleus's motion, with the expectation that the result may be negative. The conversation emphasizes that even in the opposite direction, the gamma ray must still travel at the speed of light, reinforcing the principles of relativity. The participants are encouraged to work through the calculations to solidify their understanding of these concepts.
trevorr93
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Homework Statement



An excited nucleus of krypton-80 emits a gamma ray that travels at the speed of light relative to the nucleus. The nucleus itself has a speed of 0.60c relative to the sun. Use a relativistic velocity transformation to determine the speed of the gamma ray relative to the sun if the gamma ray is emitted: a) in the direction of motion of the nucleus and b) opposite to the direction of motion of the nucleus


The Attempt at a Solution



a)

u = u' + v / 1 + vu'/c^2
u = 1 + 0.6 / 1 +(0.6)(1)/c^2
u = 1 c

Does this make sense? Can a particle not move faster then the speed of light?

b) Not sure how to approach this! would a number be negative?
 
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Looks like you fell for it :-)

A gamma ray is actually just light. That's why it can, and in fact must, travel at the speed of light. What you have shown in a) is one of the postulates of relativity (from which the transformation rule for velocities is derived), namely that light travels at the speed of light for all observers, irrespective of their relative velocity.

Now before you do b), try to think what the answer should be ... then plug in the numbers and see if you are right. If you did get a negative number, how would you explain that?
 
oh okay. so b would be equal to 1 as well because of the postulate. thank you for your help!
 
Yep*, but you should also be able to get this explicitly from the formula!

*) Actually, almost yep! - I suggest to give it a try anyway.[/size]
 
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