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## Homework Statement

in 1962 a person orbited the earth 22 times, the press stated that each orbit he aged 2millionths of a second less, then if he remained on earth.

a.assuming he was 160km above the earth, in a circular orbit, determine the time difference between on earth and the orbiting astronaut for 22orbits.

## Homework Equations

V=root(GM/R)

tau=gamma*t

## The Attempt at a Solution

v=root(6.67x10^-11*5.98x10^24/6.37x10^6+160x10^3)=7815.5m/s

distance(circumference)=2*pi*r=2*pi*(6.37x10^6+160x10^3)=4.1x10^7m

t=4.1x10^7/7815.5=5249.7s

gamma =approx (1+.5*(7815.5/3x10^8))=1.000000001

tau=gamma*t=5249.719894s

tau-t=3.563x10^-6s????? is this rite, because, i cant see anywhere i have gone wrong... used exact answers in all my calculations. i guess that is kind of close to 2x10^-6s