Renormalized Feynmann Rules (derivation)

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SUMMARY

The discussion focuses on deriving the Feynman rules associated with the kinetic counterterm in the context of renormalization within phi^4 theory. Participants clarify that the kinetic counterterm, represented as ##\delta_Z \partial_\mu \phi \partial^\mu \phi##, can be treated as a new interaction, similar to the familiar phi^4 interaction term. The derivation involves recognizing the kinetic counterterm's role in the interaction Hamiltonian, which is essential for understanding the complete set of Feynman rules in quantum field theory.

PREREQUISITES
  • Understanding of renormalization in quantum field theory
  • Familiarity with phi^4 theory and its Lagrangian formulation
  • Knowledge of Feynman rules and their derivation
  • Concept of counterterms in quantum field theory
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  • Study the derivation of Feynman rules for phi^4 interactions
  • Explore the role of counterterms in quantum field theory
  • Learn about the implications of kinetic counterterms in renormalization
  • Investigate advanced topics in quantum field theory, such as perturbation theory
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Students and researchers in theoretical physics, particularly those focusing on quantum field theory and renormalization techniques.

JCCJ
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I'm studing the basics of renormalization (with phi^4 theory) and once you write the renormalized lagrangian with the counterterms, how do you derive the feynmann rules asociated to the kinetic counterterm?

---∅--- = i(p^2 δ Z - δ m) How??...
 
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Do you know how to derive the Feynman rule for e.g. the phi^4 interaction turn? You can treat the two counterterms ##\delta_m \phi^2## and ##\delta_Z \partial_\mu \phi \partial^\mu \phi## as new interactions, and derive the associated Feynman rules for the vertices they produce in the same way you derive the Feynman rule for the familiar phi^4 interaction term.
 
Thanks!
Yes I did it,
I was puzzled because at first glance it seemed to me arbitrary regard this kinetic counterterm as part of the interaction hamiltonian and the standar kinectic term not, but I have clarified myself.
 

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