Replacing a hollow shaft with a solid shaft

  • Thread starter Thread starter stainton1
  • Start date Start date
  • Tags Tags
    Shaft Solid
Click For Summary

Discussion Overview

The discussion revolves around the problem of determining the diameter of a solid shaft that can replace a hollow shaft, while maintaining the same material properties, maximum shear stress, and torque. The context is primarily homework-related, focusing on the application of mechanical engineering principles.

Discussion Character

  • Homework-related, Technical explanation, Mathematical reasoning

Main Points Raised

  • The original poster presents a scenario involving maximum shear stress and torque, along with initial calculations for a hollow shaft.
  • Some participants suggest using the formula for the polar moment of inertia, J, for a round tube and equating shear stresses for the hollow and solid shafts.
  • One participant questions whether different equations apply for thin versus thick-walled hollow shafts.
  • Another participant argues that while there is a limit where approximate formulas can be derived for thin tubes, it is preferable to use the exact formula since the original poster's case does not involve a thin tube.

Areas of Agreement / Disagreement

Participants express differing views on the applicability of formulas for thin versus thick-walled shafts, indicating a lack of consensus on the best approach to solve the problem.

Contextual Notes

There are unresolved assumptions regarding the definitions of thin and thick-walled shafts, and the implications of using approximate versus exact formulas for the polar moment of inertia.

stainton1
Messages
3
Reaction score
0

Homework Statement



" determine the diameter of a replacement solid shaft manufactured from the same material and subjected to the same maximum shear stress and torque"

Ok so I previously calculated the following:

Maximum shear stress= 35.8 x 106
Torque= 450.117 x 103
Hollow shaft external and internal diameters= 400mm and 200mm

Homework Equations



T/J = shear stress/r

J= Pi x d4/32

r= D/2

The Attempt at a Solution



Basically I attemted it in a very long winded way which was found to be wrong when I went through it with my tutor. What happened was I went off an example we done in class which was similar but for replacing a solid shaft with a hollow one whereas I am wanting to replace a hollow shaft with a solid one. I've read the rules on here and I know its not a place to get your assignments done for you but I was hoping someone would be able to give me an explanation and point me in the right direction as my tutor isn't being to helpful. Cheers.
 
Physics news on Phys.org
stainton1: Hint: Look up or write the formula for polar moment of inertia, J1, of a round tube. Set shear stress tau1 = tau2. Substitute.
 
Last edited:
Isn't there a difference in the equations for a thin versus thick-walled hollow shaft?
 
DannoXYZ: In the limit, yes, you can obtain a different, approximate formula for a thin tube. But why bother with an approximate formula, when you can instead use the exact formula. Besides, stainton1 does not have a thin tube.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
9
Views
8K
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
4
Views
7K
Replies
5
Views
18K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K