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[SOLVED] Representation with Fibonacci numbers
Let k >> m mean that m \geq m+2. Show that every positive integers n has a unique representation of the form n = F_{k_1} + F_{k_2} + \cdots F_{k_r}, where F_{k_i} are Fibonacci nuimbers and k_1 >> k_2 >> \cdots k_r >> 0.
EDIT: The first sentence should be: Let k >> m mean that k \geq m+2.
I can show that the representation exists by induction.
To show that the representation is unique, I am also trying to use induction. The uniqueness holds for n = 1,2,3. Assume the result holds for n leq k. If k+1 has two such representations, then these two representation must be pairwise different or else the strong IH is violated. I need help drawing the contradiction in the case where the two representations are pairwise distinct. Then we have that 2k+2 is equal to a sum of distinct Fibonacci numbers leq k+1, which seems like it might be impossible, but I am not sure how to prove that.
Homework Statement
Let k >> m mean that m \geq m+2. Show that every positive integers n has a unique representation of the form n = F_{k_1} + F_{k_2} + \cdots F_{k_r}, where F_{k_i} are Fibonacci nuimbers and k_1 >> k_2 >> \cdots k_r >> 0.
EDIT: The first sentence should be: Let k >> m mean that k \geq m+2.
Homework Equations
The Attempt at a Solution
I can show that the representation exists by induction.
To show that the representation is unique, I am also trying to use induction. The uniqueness holds for n = 1,2,3. Assume the result holds for n leq k. If k+1 has two such representations, then these two representation must be pairwise different or else the strong IH is violated. I need help drawing the contradiction in the case where the two representations are pairwise distinct. Then we have that 2k+2 is equal to a sum of distinct Fibonacci numbers leq k+1, which seems like it might be impossible, but I am not sure how to prove that.
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