Resistance of a water heaters heating element?

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SUMMARY

The resistance of a water heater's heating element can be calculated using the power formula and the specific heat of water. To heat 40 gallons (151 kg) of water from 15°C to 60°C in 15 minutes requires 4184 Joules per kg, resulting in a total energy requirement of approximately 948,840 Joules. Given the voltage of 240 V, the power can be derived, and subsequently, the resistance can be calculated using the formula R = V^2 / P.

PREREQUISITES
  • Understanding of electrical power formulas (P = IV, P = I^2R)
  • Knowledge of specific heat capacity, particularly for water (4.187 x 10^3 J/(kg·K))
  • Basic concepts of thermal energy and heat transfer
  • Familiarity with unit conversions between gallons and kilograms
NEXT STEPS
  • Calculate the power required for heating water using the formula P = Q/t
  • Learn how to convert gallons to kilograms for water
  • Study the relationship between voltage, current, and resistance in electrical circuits
  • Explore the concept of thermal energy and its calculations in physics
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and electrical circuits, as well as anyone interested in understanding the principles behind household water heater operations.

Rijad Hadzic
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Homework Statement


Household water heaters use a 240 V rather than a 120 V source. What is the resistance of a water heater's heating element if it heats 40 gallons (151 kg) of water from 15 C to 60 C in 15 min

Homework Equations


P = IV
P = I^2R
I = dq/dt

The Attempt at a Solution


Honestly no clue. If anyone can give me some hints I would really appreciate this.

So far I have electrical units, V, and then I have kg, celsius, and seconds. I'm not sure how the given equations help me relate the units at all.

I need current and power, but those units do not help me at all.

I know I = dq/dt, and I thought 45 C / 900 s looks very similar to current but the units don't make sense to me...
 
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Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?
 
Chestermiller said:
Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?

I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes. Did you not study heat in freshman physics?
 
Chestermiller said:
Yes. Did you not study heat in freshman physics?

I don't think I studied it enough..

So if the specific heat of water is 4.187 x 10^3 J/(kg * k )

That means it requires 4.187 x 10^3 J to raise 1 kg of water by 1 kelvin, correct?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes, heat = thermal energy. To raise a kg water 1°C, you need 4184 Joules of heat (thermal energy).

http://www.kentchemistry.com/links/Energy/SpecificHeat.htm
 
What is the mass in kg of 40 gallons of water?
 
Last edited:
Chestermiller said:
What is the mass in kg of 40 gallons of water?

I think the asker had the converted number already [emoji846]. They wrote 151 kg.
 
Anyhow, using the heat you can now calculate the power (J/s). See that the heat is the 'J' and the time you have the 's'.

Now think about how you can get current!
 

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