Resonance & Triple Alpha Process: Why Does It Matter?

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Resonance significantly enhances the likelihood of the triple alpha process by aligning the energy levels of the reactants and products, specifically between 8Be and 4He, with an excited state of 12C. This alignment increases the probability of the reaction occurring, as it allows for a more favorable energy transfer. The concept of binding energy is crucial, as it explains why nuclear fusion and fission are exothermic; the mass of the products is less than the mass of the reactants due to energy released during the process. A slight difference in energy can affect the reaction's feasibility, with insufficient energy preventing the reaction from occurring. Understanding these principles is essential for comprehending nuclear reactions and their efficiencies.
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Why does "resonance" greatly increase the likelihood of the triple alpha process?

Why does the fact that the combined energy of 8Be and 4He is (almost) the same as the energy of an excited state of 12C greatly increase the probability of that reaction (i.e. 8Be + 4He → 12C + stuff) occurring? Apparently it doesn't have to be exactly the same, but does it make any difference if it's slightly less vs slightly more?
 
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All atoms have lower mass than the sum of their parts. This difference is called binding energy, and is the reason why nuclear fusion and fission are exothermic processes. In order for a particular reaction to take place, there must be sufficient energy so that starting product mass + binding energy + kinetic energy = end product mass + binding energy + kinetic energy. If the starting products do not have sufficient mass and kinetic energy to equal the end products, the reaction cannot occur.

Here is a link better explaining binding energy: http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/nucbin.html
 

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