How to Solve a Kinematics Equation for a Dropped Ball from a Balloon?

AI Thread Summary
A ball is dropped from a balloon ascending at 7 m/s from a height of 60 m, and the goal is to determine the time it takes to reach the ground. The relevant kinematic equation is D = ut + 1/2at^2, which leads to the quadratic equation 5t^2 + 7t - 60 = 0. The solution emphasizes using the quadratic formula to find the time, as there is no simpler method for this problem. The discussion encourages continuous learning from shared experiences in physics forums, suggesting that reviewing similar threads can enhance understanding. Ultimately, solving the quadratic equation is a straightforward part of the overall problem-solving process.
nirajnishad
Messages
16
Reaction score
0

Homework Statement


A ball is dropped from a balloon going up at a speed of
7 m/s. If the balloon was at a height 60 m at the time
of dropping the ball, how long will the ball take in
reaching the ground ?


Homework Equations


u = –7 m/s, s = 60 m, a = g = 10 m/s^2


The Attempt at a Solution


i tried solving it by using D=ut+1/2at^2
n got stuck wit this 5t^2+7t-60=0
can anyone tell me a simpler say to solve this equation?
 
Physics news on Phys.org
nirajnishad said:

Homework Equations


u = –7 m/s, s = 60 m, a = g = 10 m/s^2


The Attempt at a Solution


i tried solving it by using D=ut+1/2at^2
n got stuck wit this 5t^2+7t-60=0
can anyone tell me a simpler say to solve this equation?
You are nearly done with finding the solution. Remember that u is -7m/s, not +7m/s.

Are you familiar with the quadratic formula? Use that and you'll have t.
 
DO NOT THINK THERE IS ALWAYS A SIMPLER WAY!

See, you first made the equations. Was there any complicated part involved over there? No! There was no imagination, no setting up, no interpretation required.

So the problem itself was very simple.

Now, AS A PART OF THE PROBLEM, you have to solve a quadratic equation.

Don't give this part too much importance in your mind. Tell yourself - yeh aa gaya toh answer mil gaya. So, mindlessly, solve the quadratic equation. THAT's IT.

Set up an equation and solve it - ismein kuchh aur simple ho hi nahin sakta!
 
Keep posting more and more questions dude - we have a lot to work on! And whenever someone tells you something here - think over it and also make a note of it in your notebook or something.

At the end of a month or so - you should have the collective intelligence of all the contributors on physics forums. Sab ka experience tujhe muft main mil raha hai!
 
ALSO - DO YOURSELF A FAVOUR:

* At the bottom of the page - you have "similar threads for post title", right? Read all of them one by one, and save a copy on your hard disc as a PDF (Use A PDF printing tool like CutePDF or something.).

Its a nice way to learn - listening to the doubts of others and understanding how they had been solved. Again, at the end of the month, you should have around 500 PDFs on your hard disc if you are regular here!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top