Since y2 is never negative, x will be largest when y= 0. And when y= 0, [itex]x^2/49= 1[/itex], [itex]x^2= 49[/itex], [itex]x= \pm 7[/itex]. [itex]-7\le x\le 7[/itex]. Similarly, if x= 0 [itex]y^2/10= 1[/itex] so [itex]y= \pm\sqrt{10}[/itex]. If x is not zero, [itex]y^2[/itex] is smaller than 10 so [itex]-\sqrt{10}\le y\le\sqrt{10}[/itex].