Resultant Force: Calculating Forces with Trigonometry for a 800N and 600N Object

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Homework Help Overview

The discussion revolves around calculating the resultant force from two forces, 800N and 600N, using trigonometry. Participants are exploring how to represent these forces as vectors and how to determine the net force from their components.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the components of the forces but expresses uncertainty about the approach. Some participants suggest drawing a parallelogram of forces or converting the forces into vector form for addition. There is also a question about the correctness of the resultant force calculation.

Discussion Status

Participants are actively discussing different methods to approach the problem, with some providing guidance on vector representation and calculations. There is acknowledgment of the calculations being in a reasonable range, but no consensus on the final answer has been reached.

Contextual Notes

There is a mention of the original poster being new to the topic, which may influence their confidence in the calculations. The discussion includes checking assumptions about the force directions and the setup of the problem.

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I'm sure this problem is pretty trivial to most but apologies in advance, I'm just starting out sorry.

Homework Statement


F2-3.jpg


I'm not sure how to go about working this out due to the 800N

The Attempt at a Solution



F1 (800N) x-pos = 800 tan (90)?? , y-pos = ?
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin(30)

Homework Statement

 
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You can draw the parallelogram of forces, and the diagonal length (from your starting point) is the net force.

Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!
 
UltrafastPED said:
You can draw the parallelogram of forces, and the diagonal length (from your starting point) is the net force.

Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!

so,

F1 (800N) x-pos = 0 , y-pos = 800
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin (30)

sqrt (519.615)^2 + (500)^2 = 721.1 N

is that correct?
 
It's certainly in the correct range ... if you are unsure you should recheck your calculations.
 
UltrafastPED said:
It's certainly in the correct range ... if you are unsure you should recheck your calculations.

Ok Thank you for the help, greatly appreciated.
 

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